z^2+(-2+2i)z-10=0

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Solution for z^2+(-2+2i)z-10=0 equation:


Simplifying
z2 + (-2 + 2i) * z + -10 = 0

Reorder the terms for easier multiplication:
z2 + z(-2 + 2i) + -10 = 0
z2 + (-2 * z + 2i * z) + -10 = 0

Reorder the terms:
z2 + (2iz + -2z) + -10 = 0
z2 + (2iz + -2z) + -10 = 0

Reorder the terms:
-10 + 2iz + -2z + z2 = 0

Solving
-10 + 2iz + -2z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 2iz + -2z + 10 + z2 = 0 + 10

Reorder the terms:
-10 + 10 + 2iz + -2z + z2 = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 2iz + -2z + z2 = 0 + 10
2iz + -2z + z2 = 0 + 10

Combine like terms: 0 + 10 = 10
2iz + -2z + z2 = 10

Add '2z' to each side of the equation.
2iz + -2z + 2z + z2 = 10 + 2z

Combine like terms: -2z + 2z = 0
2iz + 0 + z2 = 10 + 2z
2iz + z2 = 10 + 2z

Add '-1z2' to each side of the equation.
2iz + z2 + -1z2 = 10 + 2z + -1z2

Combine like terms: z2 + -1z2 = 0
2iz + 0 = 10 + 2z + -1z2
2iz = 10 + 2z + -1z2

Divide each side by '2z'.
i = 5z-1 + 1 + -0.5z

Simplifying
i = 5z-1 + 1 + -0.5z

Reorder the terms:
i = 1 + 5z-1 + -0.5z

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